Comments on: Vedic Mathematics Simplified-Part 1

By: Anonymous

Anonymous — Sat, 08 Oct 2011 01:46:00 +0000

Try out the below generalization for 6 digits by making the problem as 789299 * 000056

For two digits ab x cd it is
ac (ad+bc) bd

For three digits abc x def it is
ad (ae+bd) (af+be+cd) (bf+ec) cf

Thus for four digits abcd x efgh it would be
ae (af+be) (ag+bf+ce) (ah+bg+cf+de) (bh+cg+df) (ch+dg) dh

and so on

By: Anil

Anil — Mon, 03 Oct 2011 17:44:00 +0000

Gurudev, can u show us the steps for 789299 * 56?

By: Anonymous

Anonymous — Tue, 05 Jul 2011 12:57:00 +0000

You are welcome Snowy1

By: Snowy1

Snowy1 — Thu, 30 Jun 2011 01:39:00 +0000

Thank you! Your representation of the digits along with the grouping of the digits is an excellent visual for understanding the process.

By: Akshay

Akshay — Sat, 30 Apr 2011 18:23:00 +0000

I would love to. Give me some links.
I am not that good in maths. I even suffer doing simple programming in C, Cpp. I found this quite easy.

By: Anonymous

Anonymous — Thu, 28 Apr 2011 07:18:00 +0000

Great you found the answer yourself. Strongly recommend that you work out other formulae in Vedic Maths too, it will be very easy for you as you seem to quickly grasp the logic behind its formulae

By: Gurudev

Gurudev — Thu, 28 Apr 2011 06:04:34 +0000

Great you found the answer yourself. Strongly recommend that you work out other formulae in Vedic Maths too, it will be very easy for you as you seem to quickly grasp the logic behind its formulae

By: Akshay

Akshay — Fri, 22 Apr 2011 12:44:26 +0000

I got 789299 * 56 using the same method.
just do the same multiplication from right to left on it just taking 2 numbers at a time. So we can do any kind of multiplication.

By: Akshay

Akshay — Fri, 22 Apr 2011 12:23:51 +0000

That really makes it very simple. What if the multiplication is 789299 * 56 ?

By: Gurudev

Gurudev — Wed, 14 Jul 2010 21:58:03 +0000

You can generalize the formula as follows

For two digits ab x cd it is
ac (ad+bc) bd

For three digits abc x def it is
ad (ae+bd) (af+be+cd) (bf+ec) cf

Thus for four digits abcd x efgh it would be
ae (af+be) (ag+bf+ce) (ah+bg+cf+de) (bh+cg+df) (ch+dg) dh

For five digits abcde x fghij it would be
af (ag+bf) (ah+bg+cf) (ai+bh+cg+df) (aj+bi+ch+dg+ef) (bj+ci+dh+eg) (cj+di+eh) (dj+ei) ej

and so on… Hope this helps.