While it is not known as to on what basis Pythagoras derived this theorem, this ancient Chinese proof clearly shows that the people in the ancient east were very much aware of this theorem well before Pythagoras.
(In fact, the earliest known proof of this theorem was provided by the ancient Indian Vedic mathematicians, more than 2000 years before
Pythagoras.)
Consider the
following diagram:
If you see the
Square ABCD as slightly rotated in the above diagram then it is just an
illusion. Any way, the proof given by the Chinese based on the above
diagram is as follows.
ABCD is a square
with the length of each side being (a+b). Hence,
Area of Square
ABCD = (a+b)2
- ( eq. 1 )
Now consider
another square inscribed inside ABCD i.e. EFGH whose length of the sides
is c. (Look at the above diagram). Also there are 4 right angled triangles
(every angle in a square is a right angle) inside the square ABCD. We also
see that the area of all these 4 right angled triangles is equal and is
given by 1/2 x b x a.
Area of each
right angled triangle = (1/2) x a x b - ( eq.
2 )
We can also see
that,
Area of the
Square EFGH = c2
- ( eq. 3)
Now we see that
the Area of the Square ABCD is equal to the Sum of the Areas of the 4
right angled triangles and the Area of the square EFGH. i.e.
Area of Square
ABCD = (4 x Area of a right angled trianlge) + Area of Square EFGH
Substituting
equations 1,2 and 3 in the above equation we get
=> (a+b)2
= [4 x (1/2) x a x b] + [ c2 ]
=> (a+b)2
= 2ab + c2
=> a2
+ b2 + 2ab = 2ab + c2
=> a2
+ b2 = c2
This is nothing
but the theorem what we know today in the name of Pythagoras! This proof
clearly shows that in a right angled triangle the square on the hypotenuse
is equal to the sum of the squares on the other two sides.